Question

At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . what is the electric field 0.620 cm from the center of the sphere?

Answer 1

we have given that the following:-

d=0.208cm

r=0,1cm

E=485N/C

we have to find at r=0.620cm

thus for the calculation of that we have to suppose the imaginary surface of sphere

Imaginary surfaces are spheres of radii 0.208cm and 0.620cm

485x4π 0.198²=E'x4π 0.586²

so,

E'.= 485x4π 0.198²/4π 0.586²

=19.01394/0.34396

= 55.37NC.

Answer 2

We have the equation for electric field E = kQ/
`d^(2)`

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to
`d^(2)`

So,
`(E_(1) )/(E_(2)) = (d_(2)^(2))/(d_(1)^(2))`

`E_(1)` = 485 N/C

`d_(1)` = 0.208 cm

`d_(2)` = 0.620 cm

`E_(2)` = ?

`(485 )/(E_(2)) = (0.620^(2))/(0.208^(2))`

`E_(2)` =
`(485*0.208^(2))/(0.628^(2))`

`E_(2)` = 53.20 N/C