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A cube of each side of 3m length is subjected to normal force of 36N. What will be stress?

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To calculate the the stress on the cube, we use the formula


Stress =(F)/(A)

Here, F is the normal force on the cube and A is surface area of the cube.

We know that every cube has six faces, therefore surface area of the cube,


A= 6* l^2

But according to question, the force is subjected to normal on the cube, therefore we take only one face of cube, then the surface area of the cube,


A = (l)^2

As given,
l= 3 m \ so,A=(3)^2=9 m^2

Given
F=36 N

Thus,
stress= (36)/(9) = 4\ N/m^2


User Arun Sooraj
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