Steady speed of river = 0.480 m/s
Swimming speed of student in still water = 1.40 m/s
When the student is swimming upstream the velocity he is going up = 1.40-0.48= 0.92 m/s
When the student is swimming downstream the velocity he is going down = 1.40+0.48= 1.88 m/s
Time taken to travel upstream =
![(1000)/(0.92) =1087 seconds = 18.12 minutes](https://img.qammunity.org/2019/formulas/physics/college/z93dxbyz2han30bbkpemqy4wrz5hgup72c.png)
Time taken to travel downstream =
![(1000)/(1.88) =592 seconds = 8.87 minutes](https://img.qammunity.org/2019/formulas/physics/college/5p33aa8avxuvvo2mphkcb5iq2ywom7gzld.png)
Total time taken = 18.12+8.87 = 26.99 minutes