Question

If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how many molecules of dye would be needed to visualize a single egg? Enter your answer in scientific notation rounded to two significant figures.

Answer 1

Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.

Explanation : As a single egg cell has an approximately diameter of 100 μm.

We can use this formula to calculate area of the cell membrane;

A = π
`(100)^(2) / 4`;

We can take π as 3.14 and we get;

A = 3.14 X
`(100)^(2) / 4`

Soving we get;

A = 7850 μ
`m^(2)`

Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μ
`m^(2)` but;

here 1 μ
`m^(2)` = 7850 μ
`m^(2)` dye molecules.

Therefore, 10 fluorescent molecules will need;

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.