Question

How many molecules of glycerol (c3h8o3; molecular mass = 92) are present in 1 l of a 0.5 m glycerol solution?

Answer 1

Answer is: 3.011·10²³ molecules of glycerol.

c(C₃H₈O₃) = 0.5 M; concentration of glycerol solution.

V(C₃H₈O₃) = 1 L; volume of glycerol.

M(C₃H₈O₃) = 92 g/mol; molecular mass of glycerol.

n(C₃H₈O₃) = c(C₃H₈O₃) · V(C₃H₈O₃),

n(C₃H₈O₃) = 0.5 M · 1 L.

n(C₃H₈O₃) = 0.5 mol, amount of substance.

N(C₃H₈O₃) = n(C₃H₈O₃) · Na(Avogadro constant).

N(C₃H₈O₃) = 0.5 mol · 6.022·10²³ 1/mol.

N(C₃H₈O₃) = 3.011·10²³.