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A backyard swimming pool holds 150 cubic yards (yd3) of water. what is the weight of the water in pounds?

User Mmundiff
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solution:


1yd^3=(0.9144m)^3\\ therefore,\\ 150yd^3=150yd^3*((0.9144m)^3)/(1yd^3)\\ =114.68m^3 convert m^3 to cm^3by the conversion factor as follow\\ 1m^3=(100)cm^3\\ 114.68m^3=114.68*((100cm)3)/(1m^3)\\ convert cm^3 to mL by the conversion factor as follow\\ 1cm^3=1mL\\ 114.68*10^6cm^3=114.68*10^6cm^3*(1mL)/(1cm^3)\\ =114.68*10^6mL\\ convert mL to g by the conversion factor as follow\\ 1mL=1g\\</p><p>therefore,\\ 114.68*10^6mL=114.68*10^6mL*(1g)/(1mL)\\ 114.68*10^6g\\ convert g to kg the conversion factor as follow\\ 1g=10^-3kg\\ therefore,\\ 114.68*10^6=114.68*10^6g*(10^-3kg)/(1g)\\ =114.68*10^3kg\\ convert kg to Ib by the conversion factor as follow\\ 1kg=2.2Ib\\ therefore,\\ 114.68*10^3kg=114.68*10^3kg*(2.2Ib)/(1kg)\\ =2.52*10^5Ib

User Nils
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