Answer:
The given point does not lie on the unit circle.
Explanation:
We are given the following information in the question:
A unit circle is a circle with radius of 1 unit and has its center on the origin that is with coordinates (0,0).
Thus, the equation of unit circle is of the form:
![\text{Equation of circle}\\(x-h)^2 = (y-k)^2 + r^2\\\text{where (h,k) is the cenyer of the circle, r is the radius of the circle}\\\Rightarrow \text{Equation of unit cirle}\\(x-0)^2 + (y-0)^2 = (1)^2\\x^2 + y^2 = 1](https://img.qammunity.org/2019/formulas/mathematics/college/m491xp46ow9t10jv3uxkrgbnt09zr8jao7.png)
Now, we are given the point
![\bigg(\displaystyle(-1)/(√(17)),(3)/(√(17))}\bigg)](https://img.qammunity.org/2019/formulas/mathematics/college/vpuoavmu1eakwpfiz3avb10j5o8tagdut4.png)
Putting this values in the equation of unit circle, we have:
![\bigg(\displaystyle(-1)/(√(17)),(3)/(√(17))}\bigg)\\\\x^2 + y^2 = 1\\\bigg(\displaystyle(-1)/(√(17))\bigg)^2 + \bigg((3)/(√(17))\bigg)^2 = (1)/(17) + (9)/(17) = (10)/(17) \\eq 1](https://img.qammunity.org/2019/formulas/mathematics/college/5czjvm5ehlanke80ezj9qfz6kewd6cm7vv.png)
Thus, the given point does not lie on the unit circle.