Question

the sum of two numbers is 126. The second number is 24 less than twice the first number. Find the numbers

Answer 1

You can start by making 2 equations to simulate the problem.

`x + y = 126 \\ y = 2x - 24`
Then you can subsitute the second into the y of the first equation like so:

`x + (2x - 24) = 126 \\ 3x - 24 = 126`
Then you can add 24 on both sides and get:

`3x = 150`
From here you can divide by 3 on both sides and get:

`x = 50`
After that you want to plug this x into one of the equations. I will do the second since it is simpler.

`y = (2 * 50) - 24 \\ y = 100 - 24 \\ y = 76`
Thus, the two numbers are 50 and 76.