Question

Find the point, M, that is five-sixths of the distance from A(-7, 2) to B(-1, -4).

A) (-1, -3)
B) (-2, -3)
C) (-1, -4)
D) (-2, -4)

Answer 1

Answer(-2,-3)

Explanation:

(-2, -3) The coordinates of M are (xm, ym), where xm = -7 +

5

11

(-1 - (-7)) and ym = 2 +

5

11

(-4 - 2).

Answer 2

Firstly, how many units apart is -7 from -1 (the x-coordinates)? That would be 6 units away. Multiply 5/6 by 6:

`(5)/(6)* (6)/(1)=(30)/(6)=5`

Next, how many units apart is 2 from -4? That would be, again, 6 units. Multiply 5/6 by 6.

`(5)/(6)* (6)/(1)=(30)/(6)=5`

Now, since from -7 to -1 it's increasing, add 5 to -7:

`-7+5=-2`

-2 is the x-coordinate of M.

Next, since from 2 to -4 it's decreasing, subtract 5 from 2:

`2-5=-3`

-3 is the y-coordinate of M.

Putting it together, M is at (-2,-3), or B.