Question

Find the 66th term of the following arithmetic sequence. 5,14,23,32, ...

Answer 1

first term a1 = 5, common difference d = 9

nth term = a1 + (n - 1) d

66th term = 5 + (66-1)9

= 590 answer

Answer 2

5,14,23,32, ...

n1 = 5

Common difference = 9 (14 - 5 = 5; 23 -14 = 9; 32 - 23 = 9; etc...)

So formula: An = 5 + 9(n - 1)

66th term = 5 + 9(66 - 1)

= 5 + 9(65)

= 5 + 585

= 590

Answer

590