Question

A truck slows from a velocity of 25 m/s to a stop in 70 m. What was the truck’s acceleration

Answer 1

v^2-u^2=2 x a x d

25^2-0^2=2 x a x 70

625-0=140 x a

625=140a

a=625/140

a=4.46 m/s^2

im not very sure but i think this is how you do this