Question

How do you solve
`9^(2x-1)=9^(3x-2)`

Answer 1

Since x is on the right side of the equation, switch the sides so it is on the left side of the equation.

2 ( 5 − 2 x ) − ( 1 − 5 x ) 9 − 3 x

Simplify the left side.

x + 9 = 9 − 3 x

Move all terms containing x to the left side of the equation.

4 x + 9 = 9

Move all terms not containing x to the right side of the equation.

4 x = 0

Divide each term by 4 and simplify.

x = 0

Answer 2

They have the same base, so just look at the powers. 2x - 1 = 3x - 2 Isolate the x. Subtract 3x from both sides and add 1 to both sides 2x (-3x) - 1 (+1) = 3x (-3x) -2 (+1) 2x - 3x = -2 + 1 Simplify -x = -1 Isolate the x. Divide -1 from both sides (-x)/-1 = (-1)/-1 x = 1 1 is your answer for x Hope this helps