Question

A dog is running at 6.98 m/s. His human calls to him and 3.56 seconds later he is running at 6.18 m/s. What is his acceleration during this time?

Answer 1

The equation of movement for this case is given by:

`vf = at + vo`

Where,

vf: final speed

a: acceleration

t: time

vo: initial speed

Substituting values we have:

`6.18 = a (3.56) +6.98`

Clearing the acceleration we have:

`a = (6.18-6.98)/(3.56)`

`a = -0.225 (m)/(s ^ 2)`

Answer:

his acceleration during this time is:

`a = -0.225 (m)/(s ^ 2)`