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A rectangle is 12 feet long and five feet wide.if the length of the rectangle is increased by 25% and the width is decreased by 20%, what is the change in the area of the rectangle

User JNK
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2 Answers

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First we need to find out what 25% of 12 is and what 20% of 5 is.

12 x .25 = 3 and 5 x .20 = 1

Now that that is out of the way we need to add the 3 to the twelve because the length increasing. And we need to subtract the 1 from the 5 because the width is decreasing.

12 + 3 = 15 and 5 - 1 = 4

Once you've done that, you now have the new length and width of your rectangle. To get the square foot of the new rectangle, you multiply 15 by 4.

15 x 4 = 60

User Niema Moshiri
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First of all, let's single out the 12 feet long and the 5 feet wide. We need to figure out what 25% of the length (12 feet) is. Let's divide 12 by 4. We get 3. Now, let's remember that.


Second, we need to figure out what 20% of the width (5 feet) is. Let's divide 5 by 5. We get 1. Now, let's also remember that number.


Now, we must add the numbers we got to the original length and width. For 12, we got 3, and 12+3=15. For 5, we got 1, and 5+1=6.


Now that we have the new length (15) and the new width (6), we must multiply to find the new area. 15x6=90. Using the original length (12) and the original width (5) we will multiply to find the original area. 12x5=60.


Original Area: 60 feet.

Area after increasing length and width: 90 feet.

Change in area: 30 feet.


I hope this explanation helped you out so that you can do it yourself next time. If you need anymore help, feel free to message me.

User Nulltorpedo
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