Question

The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 kg. if its density is 2.70 g/cm3 , then what is the thickness of the foil in inches?

Answer 1

To find the thickness of the aluminum foil in inches, we need to convert the dimensions and density to the same units and use the formula: thickness = mass / (length x width x density).

Step-by-step explanation:

To find the thickness of the aluminum foil in inches, we need to convert the given dimensions and density to the same units. First, let's convert the dimensions of the foil. We know that 1 yard is equal to 3 feet and 1 foot is equal to 12 inches. So, 66 2/3 yards is equal to (66 2/3 x 3 x 12) inches. Now we have the dimensions in inches.

Next, let's convert the density from g/cm3 to g/in3. We know that 1 cm is equal to 0.393700787 inches. So, 2.70 g/cm3 is equal to (2.70 x 0.3937007873) g/in3.

Finally, we can calculate the thickness of the foil using the formula: thickness = mass / (length x width x density). Plugging in the values of mass (0.83 kg), length (66 2/3 x 3 x 12 inches), width (12 inches), and density (2.70 x 0.3937007873 g/in3), we can find the thickness of the foil in inches.

Answer 2

Length of the sheet is given as

`L = (200)/(3) yards = 6096 cm`

width of the sheet is given as

`w = 12 inches = 30.48 cm`

now let say its thickness is "t"

so the volume of the sheet is given as

`V = L*w*t`

`V = 6096*30.48* t`

`V = 185806.08*t cm^3`

mass of the sheet is given as

`m = 0.83 kg = 830 gram`

now we have

`density = (mass)/(volume)`

`2.70 = (830)/(185806.08*t)`

by solving above we have

`t = 1.65 * 10^(-3) cm`

so the thickness of sheet will be above