The function factors as
... y = (x-7)(x-3)/((x-7)(x-3))
so has points of discontinuity at x=7 and x=3, where the denominator is zero. Otherwise, the value is y=1. By defining y=1 at those points, the discontinuities could be removed. The appropriate choice is ...
... x = 7, x = 3; yes . . . . . . . the 3rd selection