Question

A gasoline engine operates at a temperature of 270°C and exhausts at 180°C. Calculate the maximum efficiency of this engine. (Note that the Celsius scale is used.) 83.0 % 33.3 % 17.0 % 16.6 %

Answer 1

(1-180/270) x 100 = efficiency

1/3=33pc

Answer 2

Efficiency of gasoline engine is 16.6 %

Step-by-step explanation:

It is given that,

A gasoline engine operates at a temperature of, T₁ = 270 C = (270 + 273) K = 543 K

It exhausts at a temperature, T₂ = 180 C = (180 + 273) K = 453 K

The efficiency of this engine is given by :

`\eta=(1-(T_2)/(T_1))* 100`

`\eta=(1-(453\ K)/(543\ K))* 100`

`\eta=16.57\%`

or

`\eta=16.6\%`

So, the efficiency of this engine is 16.6 %.Hence, the correct option is (d).