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If a ball with an original velocity of zero is dropped from a tall structure and takes 7 seconds to hit the ground, what velocity does the ball have when it reaches the ground? A. 156.8 m/s B. 68.6 m/s C. 34.3 m/s D. 240.1 m/s

1 Answer

4 votes

The ball is dropped from rest, so its velocity at time
t is


v=at

where
a=-g is the acceleration due to gravity. After 7 seconds, we have


v=\left(-9.8\,(\mathrm m)/(\mathrm s^2)\right)(7\,\mathrm s)


\implies v=68.6\,(\mathrm m)/(\mathrm s)

so the answer is B.

User MQuiroz
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