Question

(05.02)A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

A right trapezoid with top side 5 feet and height 5 feet. The bottom side is extended to the right with 3 more feet.
32.5 square feet
40 square feet
187.5 square feet
375 square feet

Answer 1

You would find the area of the square witch is 25 and find the area of the triangle witch is 7.5 add them and you get 32.5 as your area

Answer 2

The area of the doghouse is
`32.5\ ft^(2)`

Explanation:

we know that

The area of trapezoid is equal to

`A=(1)/(2)(b1+b2)h`

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

`b1=5\ ft`

`b2=5+3=8\ ft`

`h=5\ ft`

substitute

`A=(1)/(2)(5+8)5=32.5\ ft^(2)`