Given coordinates (1,3) and (0,1).
In order to find the equation of line, we need to find the slope between given coordinates.
We know slope formula,
m=
![(y2-y1)/(x2-x1)](https://img.qammunity.org/2019/formulas/mathematics/high-school/im76jry3ymtqnvln3l0t8lo4zqhnce6gfm.png)
We have (x1,y1) = (1,3) and (x2,y2) = (0,1).
Plugging values of x1,y1,x2 and y2 in slope formula, we get
![m=(1-3)/(0-1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/n8k7qwvll1wd36loza78gfhu5iggy2rkey.png)
Simplifying top and bottom of the fraction we got for slope
![m=(-2)/(-1)=2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/we34z1i0m6a9u3pvtv4wygssch1a3344pv.png)
We got slope m=2.
We are given second point (0,1), where x-coordinate is 0 and y-coordinate is 1.
y-intercept is a point on y-axis, where x=0.
Therefore, y-intercept = 1.
Now, applying slope-intercept form of the linear equation
y=mx+b, where m is the slope and b is y-intercept.
m=2 and b=1.
Plugging values of m and b in slope-intercept form, we get
y=2x+1.
Therefore, point-slope form for the line is y=2x+1.