Question

2x-6(x- 3)≥5 solve for x

Answer 1

`x \leq (13)/(4)`

Explanation:

Given inequality:

`2x-6(x-3)\geq 5`

Expand -6(x - 3):

`\implies 2x-6(x)-6(-3)\geq 5`

`\implies 2x-6x+18\geq 5`

Combine like terms 2x - 6x = -4x:

`\implies -4x+18\geq 5`

Subtract 18 from both sides:

`\implies -4x+18-18\geq 5-18`

`\implies -4x\geq -13`

Divide both sides by -1, remembering to reverse the inequality:

`\implies( -4x)/(-1)\geq (-13)/(-1)`

`\implies 4x\leq 13`

Divide both sides by 4:

`\implies (4x)/(4)\leq (13)/(4)`

`\implies x \leq (13)/(4)`