Answer:-
3.77 x 10²¹ arsenic(iii) oxide molecules correspond to an LD50 value of 0.0146 for a 187 lb man
Explanation: -
Weight of man = 187 lb
=
![(187 lb)/(2.2 lb) x 1 kg](https://img.qammunity.org/2019/formulas/chemistry/college/ajsv1zzxfsayb1moh6t1k2mzxbazlwu2au.png)
= 84.8 Kg
LD50 = number of grams of a substance that is lethal to 50% of animals per kilogram of body weight
0.0146 =
![(number of grams )/(Weight of man in kg)](https://img.qammunity.org/2019/formulas/chemistry/college/irik19zukv7mvub0azbu83un9ippkt3mrf.png)
Thus
Number of grams of lethal substance = 0.0146 x 84.8
= 1.24 g
Molar mass of arsenic(iii) oxide = 197.841 g/mol
Number of moles of arsenic(iii) oxide =
![(Mass)/(Molar mass)](https://img.qammunity.org/2019/formulas/chemistry/college/sz1rl2c4uzw5v6ue22n7wqquqi6k8k6kxr.png)
=
![(1.24)/(197.841)](https://img.qammunity.org/2019/formulas/chemistry/college/ezvfpeszvv5kmz6l8apc2kyd4ni7nidgr9.png)
= 0.00627 moles
Number of molecules of arsenic(iii) oxide = Number of moles x Avogadro number
= 0.00627 x 6.02 x 10²³
= 3.77 x 10²¹