SOLUTION:
from OA=AB
\theta +\theta 45=180
2\theta =180-45
\theta =\frac{180-45}{2}=67.5
from sin rule,
\frac{OA}{sin\theta }=\frac{AB}{sin\theta }=\frac{OB}{sin45}
\therefore \frac{1}{sin67.5}=\frac{1}{sin67.5}=\frac{OB}{sin45}
\therefore OB=\frac{sin45}{sin67.5}=0.765366864730ml
\therefore net displacement OB=o.77ml