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Determine how many different values can arise by inserting one pair of parentheses into the expression 6+3⋅4+5⋅2

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(6 + 3) · 4 + 5 · 2 = 9 · 4 + 10 = 36 + 10 = 46

6 + (3 · 4) + 5 · 2 = 6 + 12 + 10 = 28

6 + 3 · (4 + 5) · 2 = 6 + 3 · 9 · 2 = 6 + 54 = 60

6 + 3 · 4 + (5 · 2) = 6 + 12 + 10 = 28 (duplicate answer)

(6 + 3 · 4) + 5 · 2 = (6 + 12) + 10 = 18 + 10 = 28 (duplicate answer)

6 + (3 · 4 + 5) · 2 = 6 + (12 + 5) · 2 = 6 + 17 · 2 = 6 + 34 = 40

6 + 3 · (4 + 5 · 2) = 6 + 3 · (4 + 10) · 2 = 6 + 3 · 14 · 2 = 6 + 84 = 72

(6 + 3 · 4 + 5) · 2 = (6 + 12 + 5) · 2 = 23 · 2 = 46 (duplicate answer)

6 + (3 · 4 + 5 · 2) = 6 + (12 + 10) = 6 + 22 = 28 (duplicate answer)

Answer: 5

User JKhan
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