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Solve for x. -ax+3b>5

User Katya S
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1 Answer

3 votes

This is a problem of inequalities. An inequality stands for the relationship between two values when they are different. In this problem, we need to solve for x. So, we have that:



-ax+3b>5


Subtracting 3b from each side of the equation, we have:



-ax+3b \mathbf{-3b}>5 \mathbf{-3b} \\ \\ -ax>5-3b


Multiplying by
-(1)/(a) the direction of the inequality changes if
a is greater than zero, so we have that solving for x the result is:



-(1)/(a)(-ax)<-(1)/(a)(5-3b) \\ \\ x<(3b-5)/(a)

User Timur Sadykov
by
8.3k points

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