Question

Help! (Solve for x)
Thanks!!!

Answer 1

`a|bx-c|=d\ \ \ \ |:a\\eq0\\\\|bx-c|=(d)/(a)\to bx-c=\pm(d)/(a)\ \ \ \ |+c\\\\bx=c\pm(d)/(a)\ \ \ \ \ |:b\\eq0\\\\x=(c)/(b)\pm(d)/(ab)\\\\x=(ac)/(ab)\pm(d)/(ab)\\\\\boxed{x=(ac-d)/(ab)\ \vee\ x=(ac+d)/(ab)}`