x = amount (kg) of 25% coper alloy
y = amount (also kg) of 70% copper alloy
Each kilogram of the 25% alloy contains 0.25 kg of copper, while each kilogram of the 70% alloy contains 0.7 kg of copper. When combined, the metalworker ends up with (x + y) kg of an alloy that should consist of 52% copper, so that it contains 0.52 (x + y) kg of copper.
The metalworker wants to make 50 kg of this new alloy, so that
x + y = 50
of which 52%, 0.52 (50 kg) = 26 kg, is copper, so
0.25x + 0.7y = 26
Solve for y in terms of x :
y = 50 - x
Substitute this into the other equation and solve for x :
0.25x + 0.7 (50 - x) = 26
0.25x + 35 - 0.7x = 26
9 = 0.45x
x = 20 → y = 30