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What is the equation of the line in slope -intercept from that is perpendicular to the line y=3/4x-2 and passes through the point (-12,10) ?

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The Slope-intercept form of the equation of a line is given by:



y=mx+b \\ \\ where \ m \ is \ the \ slope \ and \ b \ is \ the \ y-intercept


There is a line that is perpendicular to the line we are looking for, so the slope is:


m_(1)=(3)/(4)


For two perpendicular lines it is true that:



m_(1)m_(2)=-1 \\ \\ \therefore (3)/(4)m_(2)=-1 \\ \\ \therefore m_(2)=-(4)/(3)



m_(2) is the slope of the line we are looking for.


Therefore we have that:



y=-(4)/(3)x+b \\ \\ For \ the \ point \ (-12,10) \\ \\ 10=-(4)/(3)(-12)+b \\ \\ \therefore b=-6


Finally, our line is:



\boxed{y=-(4)/(3)x-6}


User Twan Van Laarhoven
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