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What are the solutions of 3d-<-10or 2d+7>9?

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3d < -10\ \vee\ 2d+7 > 9\\\\(1)\qquad3d < -10\ \ \ \ |:3\\.\qquad \qquad d < -(10)/(3)\\\\(2)\qquad2d+7 > 9\ \ \ \ |-7\\.\qquad\qquad2d > 2\ \ \ \ |:2\\.\qquad\qquad d > 1\\\\Answer:\ d < -(10)/(3)\ \vee\ d > 1\to d\in\left(-\infty,\ -(10)/(3)\right)\ \cup\ (1,\ \infty)

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