Problem N 10) Find the surface area
we know that
the surface area is equal to
SA=2*area of the base+perimeter of base*height
Find the area of the base B (area of a square)
![B=42*42=1,764\ mm^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/rf2l95qw5c25kwa30ckqtq55jeme59ryq1.png)
Find the perimeter of the base P (perimeter of a square)
![P=4*42=168\ mm](https://img.qammunity.org/2019/formulas/mathematics/middle-school/11ehhltgw84tpdlfg3ckvkjtlcyp5xj2wu.png)
height=68 mm
substitute in the formula
![SA=2*1,764+168*68=14,952\ mm^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/g578zg8fhs48hcwsuxgw6vh7vg44hpzxv3.png)
therefore
the answer Problem N 10) is
the surface area is
![14,952\ mm^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/h0onrlg9jupvz85q5iq7j3si4ccsljcqti.png)
Problem N 11) Find the volume
we know that
the volume is equal to
V=area of the base*height
find the area of the base A (area of a triangle)
![A=(1)/(2)*6*8=24\ ft^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/1drkg009kap3abv2ncez8oo8eowctu6x54.png)
height =4 ft
substitute in the formula
![V=24*4=96 \ ft^(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/r4pwn4tjwkoda0953ykmi2hayljg7l4arw.png)
therefore
the answer Problem N 11) is
the volume is equal to
![96 \ ft^(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7y7su2bbwsk6wbzxxufsx6pu1y8x4l3op3.png)