Question

The length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimiter of the rectangle is 68 feet, what are the dimensions of this rectangle?

Answer 1

Length (L): 2w + 4

width (w): w

Perimeter (P) = 2L + 2w

68 = 2(2w + 4) + 2(w)

68 = 4w + 8 + 2w

68 = 6w + 8

60 = 6w

10 = w

Length (L): 2w + 4 = 2(10) + 4 = 20 + 4 = 24

Answer: width = 10 feet, length = 24 feet