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The corners of a square lie on a circle of diameter d = 0.35 m. each side of the square has a length l. find l.

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Refer to the attached image.

As we can observe ABCD is a square, whose corners that is A,B,C and D lie on the circle.

The diameter AC = 0.35 meter.

We have to find the side of square.

Let the measure of side of a square be 'l' meter

In triangle ABC,

By Pythagoras theorem, we get


(AC)^2 = (AB)^2 + (BC)^2


(0.35)^2 = (l)^2 + (l)^2


(0.35)^2 = 2(l)^2


((0.35)^2)/(2) = (l)^2


l^2 = 0.06125

So, l = 0.25 meter

Therefore, the measure of side of the square is 0.25 meter.


The corners of a square lie on a circle of diameter d = 0.35 m. each side of the square-example-1
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