Question

Ba(oh)2 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.550 m ba(oh)2 solution.

Answer 1

Answer;

[Ba2+] = 0.550 M

[OH-] = 1.10 M

Explanation;

Each mol Ba(OH)2 releases 2 mol OH-

Ba(OH)2 -----> Ba2+ + 2OH-

Mole ratio; Ba(OH)2 :Ba2+ = 1 : 1

[Ba2+] = 0.550 M

Mole ratio; Ba(OH)2: 2OH- = 1 : 2

= 2 × 0.550 = 1.10

[OH-] = 1.10 M

This assumes complete ionization (dissociation) of Ba(OH)2.