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"determine the mass of oxygen" in a 7.9 g sample of al2(so4)3.

1 Answer

1 vote

Answer:

4.43 g of Oxygen

Step-by-step explanation:

As shown in Chemical Formula, one mole of Aluminium Sulfate [Al₂(SO₄)₃] contains;

2 Moles of Aluminium

3 Moles of Sulfur

12 Moles of Oxygen

Also, the Molar Mass of Aluminium Sulfate is 342.15 g/mol. It means,

342.15 g ( 1 mole) of Al₂(SO₄)₃ contains = 192 g (12 mole) of O

So,

7.9 g of Al₂(SO₄)₃ will contain = X g of O

Solving for X,

X = (7.9 g × 192 g) ÷ 342.15 g

X = 4.43 g of Oxygen

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