Question

The reaction of 9.2 grams of fluorine with excess chlorine produced 6.3 grams of clf3. what percent yield of clf3 was obtained? answer in units of %.

Answer 1

%age Yield = 20.12 %

Solution:

The Balance Chemical Reaction is as follow,

Cl₂ + 3 F₂ → 2 ClF₃

According to Equation ,

114 g (3 mole) F₂ produces = 184.88 g (2 moles) of ClF₃

So,

19.2 g of F₂ will produce = X g of ClF₃

Solving for X,

X = (19.2 g × 184.88 g) ÷ 114 g

X = 31.13 g of ClF₃ (Theoretical Yield)

As we know,

%age Yield = (Actual Yield ÷ Theoretical Yield) × 100

%age Yield = (6.3 g ÷ 31.3 g) × 100

%age Yield = 20.12 %