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To start a car engine, the car battery moves 1.27 ✕ 1021 electrons through the starter motor. how many coulombs of charge were moved?

User Zeck
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2 Answers

2 votes

Solution:

According to the question we have to use the formula Q=ne

Since we have given

q=1.6*10^(-19) and the car moves the electrons is 1.27*10^21

thus for calculation

1.27*10^21*1.610^(-19)

=2.03*10^3C

=203C

User Pigeongram
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5.1k points
5 votes

To calculate the amount of charge in coulombs moved by the car battery, we use the formula


Q = Nq_(e)

Here, N is the number of electron and
q_(e) is the charge of electron.

Given
N=1.27 *10^(21)  electrons and we know
q_(e) =1.6*10^(-19) C/electrons

Substituting these values in above formula we get,


Q=1.27 *10^(21)  electrons* 1.6*10^(-19) C/electrons\\\\Q=793.8C

User Arush Kamboj
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6.0k points