Question

Consider the reaction, 2 d(g) + 3 e(g) + f(g) => 2 g(g) + h(g) when e is decreasing at 0.16 mol/ls, how quickly is g increasing? give your answer to 3 decimal places.

Answer 1

2d(g) + 3e(g) + f(g) -------> 2g(g) + h(g)

As it can be seen from the equation that for every 3 moles of e consumed,=2 moles of g formed.

for every 1 moles of e consumed =
`(2)/(3)` moles of g formed

So, if e is decreasing at a rate of 0.16 mol s⁻¹

`=(2)/(3)*0.16 = 0.106 mol s^(-1)`

So when e is decreasing at 0.16 mol s⁻¹, g is increasing at a rate of 0.106 mol s⁻¹.