Question

What is the volume, in milliliters, of 6.52 g of acetone?

Answer 1

The volume of 6.52 g of acetone is approximately 0.142 mL.

Step-by-step explanation:

To determine the volume of acetone, we need to convert the mass of acetone (6.52 g) to moles using its molar mass. The molar mass of acetone is 58.08 g/mol. To convert grams to moles, we divide the mass by the molar mass: 6.52 g / 58.08 g/mol = 0.112 mol.

Next, we use the density of acetone to convert the number of moles to volume in milliliters. The density of acetone is approximately 0.79 g/mL. We can use this information to set up a conversion factor: 0.79 g acetone / 1 mL acetone.

Multiplying the number of moles by the conversion factor: 0.112 mol * (1 mL acetone / 0.79 g acetone) = 0.142 mL.

Answer 2

The mass of acetone is 6.52 g and its density is 0.791 g/mL.

The density of a substance is defined as its mass per unit volume. It is mathematically written as:

`d=(m)/(V)`

Rearranging above equation,

`V=(m)/(d)`

Putting the values,

`V=(6.52 g)/(0.791 g/mL)=8.24 mL`

Therefore, volume of acetone will be 8.24 mL.