Question

The function gx is defined as gx=6x^2+23x-4,when does g(x)=0

Answer 1

The given function is

`g(x) = 6x^2 +23x-4`

And we have to find the value of g(0), and for that we put 0 for x in the given equation.

And on substituting 0 for x in the given expression, we will get

`g(0) = 6(0)^2 +23(0) -4`

`g(0) = 0 + 0 -4 = -4`

So for the given function, the value of g(0) is -4 .

Answer 2

For this case we have the following function:

`g (x) = 6x ^ 2 + 23x-4`

What we must do is find the zeros of the function.

We have then:

`6x ^ 2 + 23x-4 = 0`

Factoring we have:

`(x + 4) (6x-1) = 0`

From here, we solve the solutions of the equation:

Solution 1:

`x + 4 = 0  x = -4`

Solution 2:

`6x-1 = 0`

`x = (1)/(6)`

Answer:

The values of x that make the equation equal to zero are:

`x = -4`

`x = (1)/(6)`