Question

At the end of a race a runner decelerates from a velocity of 11.00 m/s at a rate of 0.300 m/s2. (a) how far does she travel in the next 16.0 s? m (b) what is her final velocity? m/s

Answer 1

given that initial velocity is

`v_i = 11 m/s`

deceleration is given as

`a = -0.3 m/s^2`

now we have to find the distance covered in 16 s

`d = v_i * t + (1)/(2) at^2`

`d = 11*16 - (1)/(2)*0.3*16^2`

`d = 137.6 m`

so it will cover 137.6 m distance

part b)

in order to find the final speed

`v_f = v_i + at`

`v_f = 11 - 0.3*16`

`v_f = 6.2 m/s`

so its speed will be 6.2 m/s