Question

F(x)=9x^2

g(x)= sqrt 12-x/3

(f o g)(-4)

Answer 1

`f(x)=9x^2 \\ g(x)=(√(12-x))/(3) \\` So,first step is to write
`(fog)(-4)) =f[g(-4)] \\`

Now we start from inner paranthesis ,we need to first find value of
`g(-4) =(√(12-(-4)))/(3)\\ =(√(12+4))/(3)\\ =(√(16))/(3)\\ =(4)/(3)\\ (fog)(-4)) =f[g(-4)] =f((4)/(3)) =9(4/3)^(2) =9*(16/9) =144/9 =16`