Answer:
![\angle 1 = 225 \°\\\angle 2 = 130\°](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wx3p2ti0l80yasq1zoqc7v1gn6an6dypy3.png)
Explanation:
In this problem we have to find the measure of angle 1 and angle 2.
So, we know by definition that all internal angles of a parallelogram must sum 360°. That is,
![50\° + \angle 1 + \angle CBA + \angle 2 = 360\°](https://img.qammunity.org/2019/formulas/mathematics/middle-school/12857zzlyy82cbtz0gxht6tohczw08ptgj.png)
However, by sum of angles, and by supplementary angles, we have
![\angle CBA + 95\° = 180\°\\\angle CBA = 180\° - 95\°\\\angle CBA = 85\°](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lhy8gj4b4p3y1gxx00izp9ouiqwwn75jui.png)
Replacing this angle into the first expression, we have
![50\° + \angle 1 + \angle CBA + \angle 2 = 360\°\\50\° + \angle 1 + 85\° + \angle 2 = 360\°\\\angle 1 + \angle 2 = 360\° - 85\° - 50\°\\\angle 1 + \angle 2 = 225\°](https://img.qammunity.org/2019/formulas/mathematics/middle-school/z5vritoqcf8l4tca8q4wzfow1m4mfb35tl.png)
We know by given that
, that means BC and AD are transversals.
So, by alternate interior angles, we have
![\angle 1 = 95\°](https://img.qammunity.org/2019/formulas/mathematics/middle-school/70f0cvnd6gjjh88t6hf93gpeal60ensnlp.png)
That means,
![\angle 1 + \angle 2 = 225\°\\95\° + \angle 2 = 225\°\\\angle 2 = 225\° - 95\°\\\angle 2 = 130\°](https://img.qammunity.org/2019/formulas/mathematics/middle-school/sf5mmlls68vpgaqcnbd1vah3gws6yhm980.png)
Therefore,
![\angle 1 = 225 \°\\\angle 2 = 130\°](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wx3p2ti0l80yasq1zoqc7v1gn6an6dypy3.png)