Question

12500 J/ (106 g) (4C) reduce to one

Answer 1

29.48 J/g°C

Step-by-step explanation:

Step 1:

Data obtained from the question. This includes:

12500 J/ (106g) (4°C)

From the question given, we were asked to reduce the expression above to a single value

Step 2:

Reduction of the expression.

The reduction of 12500 J/ (106g) (4°C) can be obtained as follow:

12500 J/ (106g) (4°C) = 12500J/424g°C

= 29.48 J/g°C

Therefore, the reduction of 12500 J/ (106g) (4°C) to a single value is 29.48 J/g°C

Answer 2

The given expression is
`(12500 J)/((106g)(4^(0)C ))`

This expression denotes the specific heat of a substance which indicates a heat energy of 12500 J is involved in raising the temperature of 106 g of the substance by
`4^(0)C`. Generally, the units of specific heat are
`(J)/(g.^(0)C )`

`(12500 J)/((106g)(4^(0)C ))` =
`(12500 J)/((106g)(4^(0)C ) = 29.5 (J)/(g^(0)C )`

Therefore,
`(12500 J)/((106g)(4^(0)C ))` when reduced to one unit will be 29.5
`(J)/(g^(0)C )`