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Solve for n. F = 4/3 ​(n-1) The solution is n= F+
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Solve for n. F = 4/3 ​(n-1) The solution is n= F+

User Lubosz
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F=(4)/(3)(n-1)\ \ \ \ |\cdot(3)/(4)\\\\n-1=(3)/(4)F\ \ \ \ |+1\\\\\boxed{n=(3)/(4)F+1}

User Zachary Dale
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