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While catching fireflies,

you and a friend decide to have a competition. After
m minutes, you have (3m + 13) fireflies and your friend
has (4m + 6) fireflies. The competition lasts 3 minutes who was more

User JustLudo
by
2.6k points

2 Answers

14 votes
14 votes

Answer:

M = 3

3 x 3 + 13 = 22

4 x 3 + 6 = 18

"You" Has more.

^^ hope this helps.

Have a wonderful day!

User AlessioX
by
2.7k points
24 votes
24 votes

Answer:

Step-by-step explanation:

Lets look at the expressions with respect to the competition parameters: Expressions:You Y =3m+13Friend(F)=4m+6 1. The competition begins AFTER you and friend already caught some flies. This would be represented by the CONSTANT terms in each expression (in this case, 13 for you, 6 for friend). So the number of flies caught BEFORE THE COMPETITION would be 13+6=19 flies total 2. The competition length was "m" minutes long when flies are caught and counted. This would be represented by the VARIABLE terms in each expression (in this case, 3m for you, 4m for friend). We are not given a numeric value for the variable "m" to evaluate. So the number of flies caught DURING THE COMPETITION (timed "m" minutes long) would be 3m+4m=7m flies total ...and the number of flies per minute would be calculated as 7m÷m=7 flies per min....total #flies divided by total minutes 3. If the problem asked for the total number of flies caught by you and friend, before and after the competition 7m+19 flies total add like terms in each expression.

While catching fireflies, you and a friend decide to have a competition. After m minutes-example-1
User EvergreenTree
by
2.7k points