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5/2 (7x-15)+x>13/2-3/2


(5)/(2) (7x - 15) + x \geqslant (13)/(2) x - (3)/(2)

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5(7x - 15) + 2x ≥ 13x - 3 multiplied both sides by 2 to clear the denominator

35x - 75 + 2x ≥ 13 x - 3 distributed 5 into 7x-15

37x - 75 ≥ 13x - 3 added like terms (35x and 2x)

24x - 75 ≥ -3 subtracted 13x from both sides

24x ≥ 72 added 75 to both sides

x ≥ 3 divided both sides by 24

Answer: x ≥ 3 Notation: [3, ∞)


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