Question

A 130-lb person burns about 2300 calories to run a marathon how much energy is burned in kj chemistry

Answer 1

Data given

Energy burned in calorie = 2300 calorie

Required

Energy burned in Kj = ?

Solution

As we know that

1Cal = 0.0041868kj

So 2300 Cal = 2300 x 0.0041868

= 9.6294 Kj (answer)

energy burned in kj = ?

As we know that

1Cal= 0041868kj

So 2300 Cal= 2300 x 0.0041868 = 9.6294 Kj