Question

The average weight of top 5 fish at a fishing tournament was 13.6 pounds some of the weight of the fish are shown in the table

Answer 1

The average of a dataset is defined as the sum of its elements, divided by how many they are:

`Avg(x_1,\ x_2,\ldots,\ x_n) = (x_1+x_2+\ldots+x_n)/(n)`

So, if we call
`x` the unknown weight, we have

`A = (x+14.9+15.5+12.6+11.1)/(5) = (x+54.1)/(5)`

We want this average to be 13.6, so we have

`(x+54.1)/(5) = 13.6`

Multiply both sides by 5:

`x+54.1 = 68`

Subtract 54.1 from both sides:

`x = 13.9`

So, the heaviest fish weights 14.9 pounds