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Given the vertices of ∆ABC are A (2,-5), B (-4,6) and C (3,1), find the vertices following each of the transformations FROM THE ORIGINAL vertices:

a. Rx = 3

b. T<3,-6>


c. r(90◦, o)

Given the vertices of ∆ABC are A (2,-5), B (-4,6) and C (3,1), find the vertices following-example-1

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a) R x=3: A¹(4,-5)

B¹(10, 6) and

C(3, 1)

b) T(3,-6): A¹(5, -1),

B¹(-1, 0) and

C¹(6, -5)

c) r(90⁰, 0): A¹(5, 2),

B¹(-6, -4) and

C¹(-1, 3)


Step-by-step explanation

R x=3:

The value of y wont change for reflection along line x=3.

The distance from 3 to 2 is 1 to the left, its image should be 1 units to the right. And so it is to the other points.

3+1 = 4. A¹(4, -5)

4+3=7.

3+7=10. B¹(10,6)

Point C is on the reflection line. its point wont change. C¹(3,1)

b) T(3,-6)

Translation you just add the vector of translation to get the image.

A¹(2,5) +(3,-6) = A¹(5, -1)

B¹(-4, 6)+(3, -6) = B¹(-1, 0)

C¹(3,1)+(3, -6) = C¹(6, -5)

c) r(90⁰, 0)

This is rotation of positive 90⁰ about the origin.

For rotation of positive 90⁰ about the origin, the points of the axis just interchange and the x coordinate changes the sign.

A(2, -5) ⇒ A¹(5, 2)

B(-4, 6) ⇒B¹(-6, -4)

C(3,1) ⇒ C¹(-1, 3)




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