Question

The perimeter of a rectangle is 40. if its length is 2 more than 5 times its width, find the dimensions of the rectangle.

Answer 1

Width = w

Length = 5*w + 2

P = 2* (w + 5w + 2) = 40

P = 2*(6w + 2) = 40 You could either remove the brackets or divide by 2

6w + 2 = 40/2

6w + 2 = 20

6w = 20 - 2

6w = 18

w = 18/6

w = 3

L = 5*3 + 2

L = 15 + 2 = 17